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# Structural Analysis MCQ Quiz Test 01 Civil Engineering

#### The number of independent equations to be satisfied for static equilibrium of a plane structure is

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For 2D plan 3 equastions for 3D space 6 equations

#### If there are m unknown member forces, r unknown reaction components and j number of joints, then the degree of static indeterminacy of a pin jointed plane frame is given by

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Pin jointed plane frame Ds = m+r-2j Pin jointed space frame Ds = m+r-3j Rigid jointed plane frame Ds = 3m+r-3j Rigid jointed space frame Ds = 6m+r-6j

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#### Degree of static indeterminancy of rigid jointed plane frame having 15 members, 3 reaction components and 14 joints is

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For rigid join plan frame Ds = 3m+r-3j From given Ds = 3*15+3-3*14 Ds = 6

#### Degree of kinematic indeterminacy of a pin jointed plane frame is given by

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Kinematic Indeterminacy for Pin jointed plane frame Dk = 2j-r Pin jointed space fram Dk = 3j-r Rigid jointed plane frame Dk = 3j-(r+m)+r' Rigid jointed space frame Dk = 6j-(r+m)+r'

#### Independent displacement components at each joint of a rigid jointed plane frame are

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Fx, Fy, Mz Rotation Mz

#### If in a pin jointed plane frame (m+r)>2j, then the frame is

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Ds = m+r-2j for stable is positive then indeterminate

#### A pin jointed plane frame is unstable if

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If Ds negative then unstable

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#### Which beam shown is unstable 1
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#### Degree of kinematic indeterminacy of the beam shown is 1
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Dk = 3j-(r+m)+r' Dk = 3*6-5*5+(2-1)+(2-1) Dk = 10

#### The rigid jointed frame shown is 1
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Dk = 3m+r-3j Dk = 3*2+3-3*3 Dk = 0 Stable and determinate

#### The degree of kinematic indeterminacy of the pin jointed frame shown is 1
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Dk = 2j-r Dk = 2*3-4 Dk = 2

#### The number of independent equestions to be satisfied for static equilibrium in a space structure is

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For plane = 3 for space = 6

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#### The degree of static indeterminacy of a rigid-jointed space frame is

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rigid jointed plane frame Ds = 3m + r – 3j space frame Ds = 6m + r - 6j

#### The degree of kinematic indeterminacy of a pinjointed space frame is

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Kinematic indeterminacy Pin jointed plane frame 2j-r PIn jointed space frame 3j-r

#### The number of independent displacement components at each joint of a rigid-jointed space frame is

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2d rigid joint = 3 3d rigid join = 6 2d truss joint = 2 3d truss joint = 3

#### If in a rigid-jointed space frame, (6m+r)<6j, then the frame is

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Ds 0, Indeterminate and Stable

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