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# Structural Analysis MCQ Quiz Test 03 Q41-60 Civil Engineering

#### Bending moment at any section in a conjugate beam gives in the actual beam 1
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Conjugate beam is defined as the imaginary beam with the same span as that of the original beam The conjugate-beam method is an engineering method to derive the slope (Shear force in original beam) and deflection (Bending moment in original beam) of a beam

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#### A single rolling load of 8 KN rolls along a grider of 15 m span. The absolute maximum bending moment will be

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Max BM = Wab/L = WL/4(for mid span) = 8x15/4 = 30 KN-m

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#### Which of the following is not the displacement method

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Force method: - Primary unknown are forces. 1. Method of consistent deformation 2. Theorem of least work 3. Column analogy method 4. Flexibility matrix methd Displacement method: -Primary unknowns are the displacements. 1. Slope deflection method 2. Moment distribution method 3. Kani’s method 4. Stiffness matrix method

#### The muller-Breslau principle can be used to i) Determine the shape of the influence line ii) Indicate the parts of the structure to be loaded to obtain the maximum effect iii) Calculate the ordinates of the influence lines The correct answer is 1
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The basis of the Müller-Breslau Principle is that we can find the influence line for a determinate beam by: 1. Removing the restraint caused by the parameter that we want to find the influence line for 2. Then, displace or rotate the resulting structure by one unit.

#### Correct shear force diagram is 1
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#### Correct BMD for middle column is 1
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There will be no moment in central column.

#### Reaction at support A is 1
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#### Correct slope deflection equation is 1
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#### what is the static indeterminacy of the given fig 1
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Ds = Dse + Dsi (i) Pin jointed plane frame, Ds = m + r – 2j (ii) Pin jointed space frame, Ds = m + r – 3j (iii) Rigid jointed plane frame,Ds = (r - 3) + (3C – r’) OR 3m + r – 3j (iv) Rigid jointed space frame,Ds = (r – 6) + (6C – r‘) OR 6m + r - 6j Rigid jointed plane frame, Ds = r – 3 + (3C – r’) Ds = 6 – 3 + (3×0 - 0) Ds = 3

#### What is the degree of kinematic indeterminacy of the beam shown in fig 1
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Dk = 3j – r Dk = 3×3 – 4 Dk = 5

#### What is the degree of kinematic indeterminacy of the beam shown in fig 12.10, if the axial deformation is ignored 1
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Dk = 3j – (m + r) Dk = 3×3 – (2+4) Dk = 3

#### What is the degree of kinematic indeterminacy of the frame shown in fig. If the axial deformation is ignored 1
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Rigid jointed plane frame, (Axial deformation ignored) Dk = 3j – (r + m) + r’ Dk = 3×6 – (4+6) + 0 Dk = 8

#### What is the degree of static indeterminacy of the beam shown in fig 1
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Rigid jointed plane frame, Ds = r - 3 + [3C - r’] Ds = 6 – 3 + [3×0 – (2-1)] Ds = 2

#### The portal frame shown in fig will 1
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