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Structural Analysis MCQ Quiz Test 03 Q41-60 Civil Engineering

Bending moment at any section in a conjugate beam gives in the actual beam

conjugate beam civil engineering mega test series 1
Correct! Wrong!

Conjugate beam is defined as the imaginary beam with the same span as that of the original beam The conjugate-beam method is an engineering method to derive the slope (Shear force in original beam) and deflection (Bending moment in original beam) of a beam

For a two-hinged arch, if one of the supports settles down vertically, then the horizontal thrust

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For a symmetrical two hinged parabolic arch, if one of the supports settles horizontally, then the horizontal thrust

Correct! Wrong!

A single rolling load of 8 KN rolls along a grider of 15 m span. The absolute maximum bending moment will be

Correct! Wrong!

Max BM = Wab/L = WL/4(for mid span) = 8x15/4 = 30 KN-m

The maximum bending moment due to a train of wheel loads on a simply supported girder

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When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies

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When a uniformly distributed load, shorter than the span of the grider, moves from left to right, then the conditions for maximum bending moment at a section is that

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When a series of wheel loads crosses a simply supported girder, the maximum bending moment under any given wheel load occurs when

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Which of the following is not the displacement method

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Force method: - Primary unknown are forces. 1. Method of consistent deformation 2. Theorem of least work 3. Column analogy method 4. Flexibility matrix methd Displacement method: -Primary unknowns are the displacements. 1. Slope deflection method 2. Moment distribution method 3. Kani’s method 4. Stiffness matrix method

The muller-Breslau principle can be used to i) Determine the shape of the influence line ii) Indicate the parts of the structure to be loaded to obtain the maximum effect iii) Calculate the ordinates of the influence lines The correct answer is

Müller-Breslau Principle civil engineering mega test series 1
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The basis of the Müller-Breslau Principle is that we can find the influence line for a determinate beam by: 1. Removing the restraint caused by the parameter that we want to find the influence line for 2. Then, displace or rotate the resulting structure by one unit.

Correct shear force diagram is

shear force diagram for the fig 1
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Correct BMD for middle column is

1
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There will be no moment in central column.

Reaction at support A is

1
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Correct slope deflection equation is

1
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what is the static indeterminacy of the given fig

what is the static indeterminacy of the given fig 1
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Ds = Dse + Dsi (i) Pin jointed plane frame, Ds = m + r – 2j (ii) Pin jointed space frame, Ds = m + r – 3j (iii) Rigid jointed plane frame,Ds = (r - 3) + (3C – r’) OR 3m + r – 3j (iv) Rigid jointed space frame,Ds = (r – 6) + (6C – r‘) OR 6m + r - 6j Rigid jointed plane frame, Ds = r – 3 + (3C – r’) Ds = 6 – 3 + (3×0 - 0) Ds = 3

What is the degree of kinematic indeterminacy of the beam shown in fig

beam determinacy 1
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Dk = 3j – r Dk = 3×3 – 4 Dk = 5

What is the degree of kinematic indeterminacy of the beam shown in fig 12.10, if the axial deformation is ignored

beam determinacy 1
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Dk = 3j – (m + r) Dk = 3×3 – (2+4) Dk = 3

What is the degree of kinematic indeterminacy of the frame shown in fig. If the axial deformation is ignored

frame determinacy 1
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Rigid jointed plane frame, (Axial deformation ignored) Dk = 3j – (r + m) + r’ Dk = 3×6 – (4+6) + 0 Dk = 8

What is the degree of static indeterminacy of the beam shown in fig

beam static indeterminacy 1
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Rigid jointed plane frame, Ds = r - 3 + [3C - r’] Ds = 6 – 3 + [3×0 – (2-1)] Ds = 2

The portal frame shown in fig will

portal frame 1
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